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Resultant Force

  1. Oct 16, 2009 #1
    1. The problem statement, all variables and given/known data
    An object is at the origin. They're four perpendicular forces acting upon it. In the negative x axis, 18 N. positive x axis, 10 N. negative y axis, 8 N. and positive y axis 15 N. calculate the resultant force. What angle is it at?


    2. Relevant equations
    F=Ma?


    3. The attempt at a solution
    Not really sure how to get the resultant force. Do you just add 8+10-15-18? (since 15 and 18 are negative)? For the angle, would it be 90 degrees?
     
  2. jcsd
  3. Oct 16, 2009 #2
    You add vectors/forces by adding their x components and their y components together.
     
  4. Oct 16, 2009 #3
    So would it just be 8+10-15-18 since they are at 90? They wouldn't have any x and y components since they are not at an angle. Also what would the resultant angle be?
     
  5. Oct 16, 2009 #4
    If a force of 10N is directed upwards on the y axis it as a y compnent of 10N and an x component of 0N. Similarily if a force is directed to the right on the x axis it has a y component of 0N and an x component of 10N.
     
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