Revolutions of a tire and angle in radians thru warranty

AI Thread Summary
The discussion focuses on calculating the angle in radians and the number of revolutions a tire with a radius of 0.275 meters will make over a warranty period of 75,000 kilometers. The circumference of the tire is calculated to be approximately 1.727 meters. The correct number of revolutions is determined to be about 43,427,909.66 by dividing the total distance by the circumference. To find the angle in radians, this number of revolutions is multiplied by 2π, confirming the relationship between revolutions and radians. The calculations emphasize the importance of using precise values for accurate results.
chaotiiic
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Homework Statement


The tires on a new car have a radius of .275 meters and are warranted for 75,000km

a)what is the angle in radians that one of these tires will rotate thru in the warranty period?
b) how many revolutions does this make?

Homework Equations


1rev = 2pi radians
circumference = 2pi*r

The Attempt at a Solution


circumference = (2pi)(.275m) = 1.727m
b) 75m/.001727= 43427.9
a) 43427 *2pi = 272865
 
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Your calculation for b) is wrong. You should find the number of revolutions as {{75,000,000m}\over{1.727 {{m}\over{turn}}}}
 
Pengwuino said:
Your calculation for b) is wrong. You should find the number of revolutions as {{75,000,000m}\over{1.727 {{m}\over{turn}}}}
43,427,909.66 revolutions.
to find the angle do i multiply this by 2pi?
 
chaotiiic said:
43,427,909.66 revolutions.
to find the angle do i multiply this by 2pi?

Yes.
 

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