Rewrite curve as arclength function

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Homework Statement


Consider the curve r = <cos(3t)e^(3t),sin(3t)e^(3t),e^(3t)>
compute the arclength function s(t) with the initial point t = 0.


Homework Equations


s = integral |r'(t)|dt


The Attempt at a Solution


Okay so if you work all of this out it turns out it's not as bad as it looks.. it's set up to come out really nicely it appears. I end up with

s = 3^(1/2)e^(3t)

but my online homework program is saying that this is wrong... Do I ever use the information that the initial point is t = 0? I don't understand why they need to tell me that...
 
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When you put ##t=0## you aren't getting ##s(0)=0## like the problem asks. You need to calculate$$
s(t) - s(0) = \int_0^t|r'(t)|dt$$with s(0)=0. I'm guessing you didn't handle the lower limit correctly.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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