Rewriting a Riemann Sum Statement: Identify the Function

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Homework Statement



We were asked to identify and rewrite the following statement. Not sure how to do a sum sign here so will just write sum for it:

sum (lower i=0)(upper 2n) (i/n)^2 (1/n) = 1/n^3[ 1^3 + 2^3 + 3^3 + ... + (2n)^2

Homework Equations



I believe this is a Riemann Sum but not sure how to rewrite it.

The Attempt at a Solution



I have :

I'm still looking for how to rewrite.


Thanks,
glenn
 
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cybercrypt13 said:

Homework Statement



We were asked to identify and rewrite the following statement. Not sure how to do a sum sign here so will just write sum for it:

sum (lower i=0)(upper 2n) (i/n)^2 (1/n) = 1/n^3[ 1^3 + 2^3 + 3^3 + ... + (2n)^2
\sum_{i=0}^{2n}\frac{i^2}{n^3}
Note that this is NOT i3!

Homework Equations



I believe this is a Riemann Sum but not sure how to rewrite it.

The Attempt at a Solution



I have :

I'm still looking for how to rewrite.


Thanks,
glenn
Do you know a formula for the sum of squares: 1+ 4+ 9+ 16+ ...?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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