- #1
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Can someone help me show the following:
[tex]\int_0^{\infty}r^k e^{-a r} dr=\frac{k!}{a^{k+1}}[/tex]
I tried to use the polynomial expansion of e^x:
[tex]\sum_{n=0,1...} \frac{x^n}{n!}[/tex]
...but I get stuck pretty fast. Can someone give me a few hints?
Thanks!
[tex]\int_0^{\infty}r^k e^{-a r} dr=\frac{k!}{a^{k+1}}[/tex]
I tried to use the polynomial expansion of e^x:
[tex]\sum_{n=0,1...} \frac{x^n}{n!}[/tex]
...but I get stuck pretty fast. Can someone give me a few hints?
Thanks!