Can anyone help with finding the Riemann sum for f(x)=x^3?

AI Thread Summary
To find the Riemann sum for the function f(x)=x^3 over the interval [1,5] using the equipartition P=(1,2,3,4,5), the right-hand endpoints are used for the calculations. The Riemann sum can be computed by evaluating the function at these endpoints and multiplying by the width of the intervals. Additionally, a general formula for the Riemann sum for n intervals can be derived using the summation formula for cubes, specifically sum(i^3)=1/4n^2(n+1)^2. The discussion emphasizes the importance of sharing initial attempts and specific difficulties to receive effective assistance.
dan
Hello there, can anyone help me here as I'm finding it difficult to tackle this question.

Consider f(x)=x^3 on the interval [1,5].
Find the Riemann sum for the equipartition P=(1,2,3,4,5) into 4 intervals with x_i^* being the right-hand endpoints (ie. x_i=a+hi)

Then find a formula for the Riemann sum for an equipartition P_n into n intervals and right-hand endpoints. Use the summation formulae
sum(i^3)=1/4n^2(n+1)^2, upper lim=n, lower lim;i=1.

Cheers
 
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Hi dan,
I believe this belongs in Homework Help and the policy there is that you tell us what you got so far, and where you are stuck. Then we can help.
 
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