Right Hand rule, explain please?

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Homework Help Overview

The discussion revolves around the right-hand rule, a concept commonly used in physics to determine the direction of a cross product in a right-handed coordinate system. Participants are exploring the definition and application of this rule, particularly in relation to vector operations.

Discussion Character

  • Conceptual clarification, Exploratory

Approaches and Questions Raised

  • The original poster seeks a clearer understanding of the right-hand rule, expressing a preference for visual aids. Participants discuss the mechanics of the rule, including the relationship between vectors and the resulting direction of the cross product.

Discussion Status

Some participants have found the explanations provided to be helpful, indicating that the discussion has led to a better understanding of the right-hand rule. There is an acknowledgment of the difficulty in conveying the concept without visual demonstrations.

Contextual Notes

The original poster does not present a specific problem but rather seeks clarification on a fundamental concept, suggesting a focus on understanding rather than solving a particular homework question.

elephantorz
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[SOLVED] Right Hand rule, explain please?

I don't have a problem, I just have issues with understanding the right-hand rule, if someone could explain it (with pictures if possible) I would appreciate it, although it might be better in person because I could see the motion.
 
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Consider the following diagram,

Axes_800.gif


The right-hand rule is defined such that it conforms to the right-hand coordinate system. In the right-handed coordinate system with the usual unit vectors (i, j, k) the cross product between i and j gives, by definition, k,

i X j = k

Which simply means that if one rotates the x-axis counter-clockwise by [itex]\pi/2[/itex] such that it lies collinear with the y-axis, then the result is the z-axis. The right-hand rule is commonly used to determine the direction of a cross product, especially in physics problems.

Consider the cross product describe above (iXj), which basically means rotating the vector i (the x-axis) toward the vector j (y-axis). Now, take your right-hand and keeping your thumb straight (as if giving the 'thumbs up') curl your fingers in the direction which the x-axis is rotating (in this case toward the y-axis). Your thumb should now be pointing straight upwards, in the direction of k (the z-axis).

Now consider the following cross product,

j X i

Using the same method as above try to curl your fingers in the direction of rotation (i.e. from the y-axis to the x-axis), you'll probably find that you'll have to turn your hand upside down. If you have done it correctly, your thumb should be pointing direction downwards (towards the negative z-axis). Hence, you have used the right hand rule to determine the cross product,

j X i = -k

Indeed, it is very difficult to describe the right-hand rule without demonstrating it. However, I hope you've found my post useful.
 
It was, very useful, I had never had it explained to me like that, which makes more sense seeing the diagram, thanks!
 
elephantorz said:
It was, very useful, I had never had it explained to me like that, which makes more sense seeing the diagram, thanks!
Glad to be of service :smile:
 

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