Ring of charge electric potential

[Panphobia]

Homework Statement

The ring is in the z,y plane.
D = 2m
R = 4m
Q = 8 * 10^-6 C
X = distance to the edge
λ = dQ/dX
dX = rdθ
dQ = infinitely small charge
dX = infinitely small arc of ring

What is the potential difference at the point D perpendicular to the centre of the ring?

Homework Equations

\int \frac{kdQ}{X}

The Attempt at a Solution

\int \frac{kλrdθ}{(D^2+R^2)^{1/2}}
After this how do I get it in terms of dθ?

 

[Tanya Sharma]

What is the question ? Are you required to find the potential of the ring at a point 2m away from the center ,and lying on the axis of the ring ?

 

[Panphobia]

Yea I gave the question after all the variables were specified

 

[Tanya Sharma]

What is the problem ? Just integrate the expression with appropriate limits.The variable of integration is θ .

 

[Panphobia]

Thats it?

 

[Tanya Sharma]

Thats it?

What does that mean ?

 

[Panphobia]

So what are we integrating to 0 to 2pi?

 

[Tanya Sharma]

Yes... the range of θ is 0 to 2pi .