Ring Theory: Show Phi(a)= a^p is Isomorphism

  • Thread starter Thread starter ECmathstudent
  • Start date Start date
  • Tags Tags
    Ring Theory
ECmathstudent
Messages
36
Reaction score
0

Homework Statement


Given a commutative ring R with a prime characteristic p, show that the mapping phi:R-->R defined by phi(a)= a^p is a isomorphism

Homework Equations


Fermat's little theorem(I think)

The Attempt at a Solution



I'm pretty sure Fermat's theorem must have something to do with this. Or I could be completely wrong, it just popped into my head very quickly and I haven't really been able to find out if it applies in this case (some sort of generalization, at least), how to show it applies, or come up with any other idea.

Also, sorry for the formatting, I don't know LaTeX
 
Physics news on Phys.org
You will want to consider \phi(a+b) \mod p.
 
roight
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top