A coil of resistance 8.0 ohms and self-inductance 4.0 mH is suddenly connected across a constant potential difference of 100 V. Let t = 0 be the time of connection, at which the current is zero. Find the current I and its rate of change dI/dt at times (a) t = 0, (b) t = 0.1 s, (c) t = 0.5 s, and (d) t = 1.0 s.
If=E_o / R = 100V/8.00ohms = 12.5A
T(time constant)= L/R = 4.0 mH/8ohms = .500 ms
The Attempt at a Solution
Substitute If and T to obtain
I = (12.5A) (1-e^(-t/.500ms))
Express dI/dt :
dI/dt = 12.5A(-e^(-t/.500ms)) <--- here is where im stuck. Seems like there should be a numer in the thousands to multiply with units s^-1 to cancel out the other units
which in return would yiels aan anser like:
Then substitute all the reset of the values in.
Not sure what i am missing here Please help me!!!