RLC Circuit Resonance Frequency for WRUF Broadcast

AI Thread Summary
WRUF broadcasts at a frequency of 103.7 MHz, which corresponds to a wavelength of approximately 2.89 meters. To tune an RLC circuit to this radio station, the resonance frequency should match the broadcast frequency of 103.7 MHz. The resonance frequency is achieved by adjusting the capacitance in the circuit. When the resonance frequency aligns with the station's frequency, the potential difference across the circuit reaches its maximum, allowing for optimal reception. Therefore, tuning the RLC circuit to 103.7 MHz is essential for receiving the broadcast.
elink24
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Homework Statement


a) WRUF broadcasts at 103.7 MHz, what is the wavelength associated?

b) If you were to use an RLC circuit to tune to this radio station, what resonance frequency would you tune to?


Homework Equations


f(resonance)= 1/(2\pi\sqrt{LC})


The Attempt at a Solution


a) \lambda= C/f
\lambda= (3*10^8)/(103.7*10^6)= 2.89m

b) I was not given any information besides the broadcast frequency, or the wavelength which I obtained. I do not see how I can find the resonant frequency with such limited information. If anyone could give me a prod in the right direction, I'd appreciate it!
 
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To receive any radio station, you have to tune the RCL circuit such that its resonance frequency equals the frequency of the radio station.
 
So the RLC circuit would simply need to be tuned to 103.7 MHz to receive that particular station? Maybe I overthought this...
 
elink24 said:
So the RLC circuit would simply need to be tuned to 103.7 MHz to receive that particular station? Maybe I overthought this...
When you tune any radio station, actually you are changing capacity of the capacitor of the LCR circuit. When the resonance frequency matches the frequency of the radio station, potential difference across LCR circuit is maximum for that frequency. Thus the station is received.
 
Oh I see, thanks for your help!
 
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