RMS voltage, phase angle, AC circuits

AI Thread Summary
The discussion revolves around understanding the concepts of RMS voltage and phase angle in AC circuits, particularly in relation to a circuit with a 200-volt peak voltage and a 53 microfarad capacitor. RMS voltage is defined as the peak voltage divided by the square root of two. The phase angle represents the difference in phase between the voltage and current in the circuit. The user seeks clarification on these concepts, indicating that they have equations for other calculations but need a deeper understanding of phase angle and RMS. Overall, the thread emphasizes the importance of these terms in analyzing AC circuits.
kevinlikesphysics
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Homework Statement




An AC power supply with a peak volatge output of 200 volts, operating at 60 Hz, is connected to a 53 microFurad capacitor

A) what is the difference in phase angle between the applied voltage and the current

B) what is the rms current in the circuit

C) what is the rate of energy dissipated to heat in the capacitor



Homework Equations



Several,



The Attempt at a Solution



I really just need an explanation of phase angle and what RMS is. The other stuff I have equations for and seems pretty straight forward.

Any information or links about phase angle and its use/purpose/definition would be greatly appreciated.
 
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hi kevinlikesphysics! :smile:
kevinlikesphysics said:
I really just need an explanation of phase angle and what RMS is. The other stuff I have equations for and seems pretty straight forward.

rms voltage is peak voltage divided by √2 :smile:

phase angle is the difference in phase between the https://www.physicsforums.com/library.php?do=view_item&itemid=301" in AC circuits) …

in this case, you should be able to get it from the basic https://www.physicsforums.com/library.php?do=view_item&itemid=112" equation relating voltage and charge (remember, current = charge per time :wink:)
 
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