Rocket in Deep Space: Momentum Maximization

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The discussion centers on maximizing momentum for a rocket in deep space, where external forces are negligible. The momentum equation is given as p=mv_{i}+muln(m_{i}/m), and the user derived the condition for maximum momentum as ∂p/∂m=0, leading to m=m_{i}e^{(v_{i}/u)-1}. However, there is a debate about whether this condition truly represents a maximum, with hints that ∂p/∂m=0 is necessary but not sufficient for a maximum. Ultimately, it is confirmed that the user's solution does yield maximum momentum within the specified mass range and under the assumption that v(i) can be zero. The conclusion emphasizes that the derived solution is indeed valid for maximizing momentum in the given context.
Sekonda
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Hey,

I have a question on a rocket in deep space (all external forces negligible), basically I'm doing something wrong the latter part of the question - maximizing the momentum via differentiation, here's the question:

Rocket.png


So the momentum at a given mass 'm' is :

p=mv_{i}+muln(\frac{m_{i}}{m})

I attained a derivative of respects to 'm' as:

\frac{\partial p}{\partial m}=v_{i}+u(ln\frac{m_{i}}{m}-1)=0

Giving 'm' as :

\LARGE m=m_{i}e^{\frac{v_{i}}{u}-1}

Which is wrong according to the solutions unless I assume v(i)=0 which I don't think I should.

Where am I going wrong?

Thanks guys,
SK
 
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Remember that momentum is a vector not a scalar.
 
Are you sure that is a maximum? (hint: ∂p/∂m = 0 is a necessary but not sufficient condition for a maximum).
 
Sekonda said:
Giving 'm' as :

m=m_{i}\,e^{\frac{v_{i}}{u}-1}
That's correct.

Which is wrong according to the solutions unless I assume v(i)=0 which I don't think I should.
That is a reasonable assumption for this problem.
 
Filip Larsen said:
Are you sure that is a maximum? (hint: ∂p/∂m = 0 is a necessary but not sufficient condition for a maximum).

I can see that my earlier comment, made on the assumption that you did have an error somewhere, could be read to imply that your solution is not a maximum, when in fact it is. I apologize for any confusion my comment may have caused.

After doing the actual calculation I too concur that your solution gives maximum momentum in the interval 0 ≤ m ≤ mi or, equivalently, when vi ≤ u.
 
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