Rocket Mass & Velocity: Calculating Gas Ejection Rate

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To calculate the gas ejection rate for a rocket traveling at 1950 m/s and desiring an acceleration of 1.4 m/s², the relevant equation is M*dv/dt = ∑F(ext) + v(rel)*dM/dt. The external force at an altitude of 6600 km is not simply mg but must account for gravitational force using the formula F=GmM/r², where r is the distance from the Earth's center. The gravitational force varies with altitude, necessitating a correct calculation of g at that height. Understanding these forces is crucial for determining the correct rate of gas ejection. Accurate calculations will lead to the desired acceleration.
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Homework Statement


A rocket traveling 1950 m/s away from the Earth at an altitude of 6600 km fires its rockets, which eject gas at a speed of 1300 m/s (relative to the rocket).
If the mass of the rocket at this moment is 2.25×104 kg and an acceleration of 1.4 m/s^2 is desired, at what rate must the gases be ejected?

Homework Equations



M*dv/dt = \sum F(ext) + v(rel)*dM/dt

The Attempt at a Solution



I thought i could just solve for dM/dt in the above equation and plug in the numbers to get the answer but that didnt work. I think my problem is with finding all the external forces, which i think is just mg. I just need a hint to start.
 
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The external force at altitude of 6600 km is not mg.

ehild
 
ehild said:
The external force at altitude of 6600 km is not mg.

ehild

so when I find g is that all i have to find? ->for the external force?
 
Last edited:
The external force is gravity that depends on the altitude.
F=GmM/r2, and r is the distance from the centre of Earth, r=radius or Earth + altitude

ehild
 
alright thanks
 
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