I Rocket Thrust: Power Your Launch Into Space

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    Rocket Thrust
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The discussion centers on the reference frame of a rocket, emphasizing that using the rocket's frame simplifies calculations. There is confusion regarding the formula for exhaust velocity relative to the rocket, with a correction noted that it should be "v" instead of "u." The relationship between the rocket's speed after expelling exhaust and the velocity of the ejected material is clarified as v + delta v - U. The source of this information is linked to HyperPhysics. Overall, the conversation highlights the importance of clarity in reference frames and velocity calculations in rocket physics.
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Confusion of thrust of a rocket
I saw the information of thrust of a rocket in the hyperphysics website, but I cant understand it.
1.why do the problem need to observe in two frame ( from an external framework and rocket frame of)?
2.why do the exhaust velocity relative to the rocket u=u+deltav-U?

Thank You
thrust of rocket2.png
 
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The reference frame of the rocket is the easiest one. You can always choose whatever reference frame you want but why make it harder than needed?
2.why do the exhaust velocity relative to the rocket u=u+deltav-U?
Where do you get that from? The exhaust velocity relative to the rocket is u which is not equal to u+deltav-U.
 
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mfb said:
The reference frame of the rocket is the easiest one. You can always choose whatever reference frame you want but why make it harder than needed?Where do you get that from? The exhaust velocity relative to the rocket is u which is not equal to u+deltav-U.
typo,why do the exhaust velocity relative to the rocket u=v+deltav-U? should be "v" not "u".
i get the information from this website: http://hyperphysics.phy-astr.gsu.edu/hbase/rocket.html#c1
thank u for your reply
 
The rocket speed after expelling the exhaust is v+delta v, the ejected material moves at U by definition. They just calculate the difference, which is v + delta v - U
 
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