What is the Solution to the Roller Coaster Apparent Weight Problem?

AI Thread Summary
The discussion focuses on the apparent weight difference experienced by a rider on a roller coaster during a vertical loop, specifically noting a difference of 6 g's between the top and bottom of the loop. Participants emphasize the importance of understanding centripetal force, which varies at different points in the loop. One user shares their struggle with the equations related to weight and acceleration, indicating they are preparing for the MCAT rather than completing a homework assignment. The conversation encourages sharing previous attempts to solve the problem for better assistance. Overall, the thread seeks to clarify the physics behind apparent weight changes in roller coasters.
joseph harris
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Show that a roller coaster with a circular vertical loop. The difference in your apparent weight at the top of the circular loop and the bottom of the circular loop is 6 g's-that is, six times your weight. Ignore friction. Show also that as long as your speed is above the minimum needed, this answer doesn't depend on the size of the loop or how fast your go through it. I tried solving this but I'm very frustrated can anyone help?:smile:
 
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We do need to see what you've already tried, so we know you aren't just trying to get an easy answer out of us.

A quick hint, though - have you considered the centripetal force necessary, and where that force is going to come from? It'll be different at the top of the loop and at the bottom.
 
Pls explain what you tried and where you got stuck.
 
Diane,

I have used the relationship of: w-MG=MA Solving for w We have W+Mg+MA

W+MG+m(.5g)=3/2mg. I still have not been able to solve. This is not a homework problem but a MCAT review problem. Thanks
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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