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Nanuven
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[SOLVED] Rolling Forces
A bowler throws a bowling ball of radius R = 11 cm down a lane. The ball slides on the lane with initial speed vcom,0 = 6.0 m/s and initial angular speed 0 = 0. The coefficient of kinetic friction between the ball and the lane is 0.19. The kinetic frictional force fk acting on the ball causes a linear acceleration of the ball while producing a torque that causes an angular acceleration of the ball. When speed vcom has decreased enough and angular speed has increased enough, the ball stops sliding and then rolls smoothly.
(a) What then is vcm in terms of ?
___________m·[tex]\omega[/tex]
(b) During the sliding, what is the ball's linear acceleration?
___________m/s2
(c) During the sliding, what is the ball's angular acceleration?
___________rad/s2
(d) How long does the ball slide?
___________s
(e) How far does the ball slide?
___________m
(f) What is the speed of the ball when smooth rolling begins?
___________m/s
I am utterly lost in this problem. I assume that since the ball is sliding the force of kinetic friction is applying a torque onto the ball so:
T = FkR
T = Fk(.11m)
and Fk = uN so
T = (.19)(9.8)(.11)m
so
T = .2048 * m
now, I'm lost. Any pointers in the right direction?
Homework Statement
A bowler throws a bowling ball of radius R = 11 cm down a lane. The ball slides on the lane with initial speed vcom,0 = 6.0 m/s and initial angular speed 0 = 0. The coefficient of kinetic friction between the ball and the lane is 0.19. The kinetic frictional force fk acting on the ball causes a linear acceleration of the ball while producing a torque that causes an angular acceleration of the ball. When speed vcom has decreased enough and angular speed has increased enough, the ball stops sliding and then rolls smoothly.
(a) What then is vcm in terms of ?
___________m·[tex]\omega[/tex]
(b) During the sliding, what is the ball's linear acceleration?
___________m/s2
(c) During the sliding, what is the ball's angular acceleration?
___________rad/s2
(d) How long does the ball slide?
___________s
(e) How far does the ball slide?
___________m
(f) What is the speed of the ball when smooth rolling begins?
___________m/s
The Attempt at a Solution
I am utterly lost in this problem. I assume that since the ball is sliding the force of kinetic friction is applying a torque onto the ball so:
T = FkR
T = Fk(.11m)
and Fk = uN so
T = (.19)(9.8)(.11)m
so
T = .2048 * m
now, I'm lost. Any pointers in the right direction?
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