a 16lb yo-yo is resting on a horizontal table and is free to roll. The dimensions are r = 4in and R = 12in and the radius of gyration about the CM is 6in. A cord is wrapped around the inner radius, the passes over a perfect pulley, and is attached to a 8lb block.
Find acceleration of 8lb block and the tension in the cord
(answers are 4.830ft/s^2 and 6.792lb)
F = ma
torque = I*alpha = F*moment-arm
Iaxis = Icm + mh^2
I = (radius-gyration)R^2
The Attempt at a Solution
there are two accelerations a1 (weight) and a2 (yo-yo).
(16/32slugs)*a2 = T
I at table contact point = 90slug*in^2
net torqe at table contact point = 90slug*in^2 * alpha = T(12in - 4in)
T = 11.25*alpha and 0.5slugs * a2 = T
for weight, (8/32slugs)a1 = 8lb - T
so far, I have 4 unknowns and 3 equations so I can't solve for anything. What equation am I missing? i don't know how to find a relationship between alpha and a2 (i thought a2 = 12in*alpha but that doesn't work out right).
thanks in advance