I Rotating Coordinates

  • Thread starter Nusc
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754
2
If one rotates a tangent plane on a curved surface, this point can be expressed as follows:

x' = x cos(theta) - y sin(theta)
y' = x sin(theta) + y cos(theta)

One solves for x and y and computes based on the deviation of the deviation.

My question is: would the answer differ if you choose a different point say:

x' = x cos(theta) + y sin(theta)
y' = - x sin(theta) + y cos(theta)

note the negative sign.
 

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Can you please explain your question some more? How could the answer NOT change if you change the equations and the resulting values?
 
754
2
Can you please explain your question some more? How could the answer NOT change if you change the equations and the resulting values?
In the attached drawing, I can could approach this new point as

x' = x cos(theta) - y sin(theta)
y' = x sin(theta) + y cos(theta)

or

x' = x cos(theta) + y sin(theta)
y' = - x sin(theta) + y cos(theta)

From what you see in the diagram, how would you justify which coordinates?
 

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754
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If you cannot, then what should the second pair of coordinates look like visually?
 

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I still don't understand. In the diagram you posted, where are the points (x,y), (x',y'), and the angle theta?
 

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