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Rotatioanl dynamics

  1. Feb 8, 2004 #1
    The engine of an aircraft propeller delivers an amount of power 171. hp to the propeller at a rotational velocity of 2310 rev/min. I found the torque produced to be 527.612 N*m
    How can i find the work done by the engine in one rev of the propeller?
     
  2. jcsd
  3. Feb 8, 2004 #2
    Power is the rate at which work is done.

    171 hp = 746 W = 746 J/s

    You have how many revs / s ?

    (J/s)/(r/s) = J/r
     
  4. Feb 8, 2004 #3

    jamesrc

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    use this equation to find the work done: W = τθ (it's the rotational analog to W = Fd; realize that it's still a dot product, but we've simplified already)
     
  5. Feb 8, 2004 #4

    jamesrc

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    Touche, gnome.

    ACLerok: you should get the same answer either way.
     
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