I Rotation and Translation coordinates

AI Thread Summary
The discussion focuses on the relationship between generalized coordinates and kinetic energy in a holonomic system. It clarifies that while certain coordinates like r (translation) directly affect kinetic energy, others like θ (rotation) do not, as T is dependent on their time derivatives (e.g., \(\dot{\theta}\)). The distinction is made that a coordinate is considered a translation or rotation based on whether the kinetic energy remains invariant under specific transformations. In spherical coordinates, the polar angle θ does not represent a true rotation due to its time-dependent nature, while φ does correspond to a fixed rotation axis. This nuanced understanding is essential for analyzing the dynamics of systems in classical mechanics.
FrederikPhysics
Messages
8
Reaction score
0
I am currently reading Goldstein's Classical mechanics and come on to this problem. Let q1,q2,...,qn be generalized coordinates of a holonomic system and T its kinetic energy. qk correspondes to a translation of the entire system and qj a rotation of the entire system around some axis, then ∂qjT=∂qkT=0 since velocities are not affected by a translation of the origin or a rotation of the coordinate axes.
Now take as an example the kinetic energy of a single particle in spherical coordiantes, here the polar angle θ correspondes to a rotation of the system, but T is dependent on θ. r correspondes to a translation of the particle and therefore the system but T depends on r. How should I undersand this?
Mvh. Frederik
 
Mathematics news on Phys.org
T does not depend on ##\theta## but on ##\dot\theta## which is a different generalized coordinate...
idem ##r## and ##\dot r##
 
Actually it is a definition:
"the system admits translation along the generalized coordinate ##q^j##"##\Longleftrightarrow## ##"\frac{\partial T}{\partial q^j}=0"##. Or equivalently iff ##T## is invariant under the group ##q^j\mapsto q^j+s,\quad s\in \mathbb{R}##
It doesn't matter what is ## q^j##. If ##q^j## is an angle then we say that the system admits a rotation.
 
BvU said:
T does not depend on ##\theta## but on ##\dot\theta## which is a different generalized coordinate...
idem ##r## and ##\dot r##

For a system consisting of one particle with mass m one writes T=½m(dr/dt2+r2 dθ/dt2+r2sin2θ dφ/dt2) in spherical coordinates, θ being the polar angle and φ the azimutal angle, that makes T=T(r, θ, dr/dt, dθ/dt, dφ/dt).
 
O now I see what you want. This is a good question indeed. It is because ##\theta\mapsto \theta+s## is not a rotation of the space about a fixed axis. Look how all the points of the space conduct under this transformation
 
  • Like
Likes BvU and FrederikPhysics
Okay, so one might say:
Let ##T=\frac{1}{2}m\dot{\textbf{r}}\cdot\dot{\textbf{r}}## be the kinetic energy of a one particle system, ##\textbf{r}## the position vector in some frame and q a set of generalized coordinates. ##q_{k}## is called a translation coordinate when there exists a vector ##\textbf{n}## such that ##\frac{\partial \textbf{r}}{\partial q_{k}}=\textbf{n}## fulfilling ##\dot{\textbf{n}}=\textbf{0}##. Then ##\frac{\partial T}{\partial q_{k}}=m\dot{\textbf{r}}\cdot\frac{d}{dt}\frac{\partial\textbf{r}}{\partial q_{k}}=0##.
When this is true ##q_{k}##is said to translate the system in the direction of ##\textbf{n}##.

##q_{j}## is called a rotation coordinate when there exists a vector ##\textbf{n}## such that ##\frac{\partial \textbf{r}}{\partial q_{j}}=\textbf{n}\times\textbf{r}## fulfilling ##\dot{\textbf{n}}=\textbf{0}##. Then ##\frac{\partial T}{\partial q_{j}}=m\dot{\textbf{r}}\cdot\frac{d}{dt}\frac{\partial\textbf{r}}{\partial q_{j}}=0##.
When this is true ##q_{k}## is said to rotate the system around the direction of ##\textbf{n}##.
The generalazation to more particles follows naturally.

Within this definition the coordinates r and ##\theta## of the spherical coordinate system, in general neither translates nor rotates the system since the r unitvector, ##\hat{\textbf{r}}##, depends on time and the rotation axis of ##\theta##, nθ, depends on time. The coordinate φ is a rotation coordinate since its rotation axis nφ correspondes to the fixed polar axis.
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Back
Top