Rotation of functions

  • #1
59
5
Summary:
How is it possible to rotate a function (for example the 3D wave function) by an infinitesimal angle by using derivatives?
I was solving a problem for my quantum mechanics homework, and was therefore browsing in the internet for further information. Then I stumbled upon this here:
F5F459AD-E4C6-4951-A918-DA2E8E80B8D9.jpeg

R is the rotation operator, δφ an infinitesimal angle and Ψ is the wave function.
I know that it is able to rotate a curve, vector... with a rotation matrix. But how is it possible to rotate a function only with derivatives? I tried to rephrase a function f(x) as a curve, applying the 2D rotation matrix and small angle approximation and convert it back to an explicit function f(x). But I did not get the same answer.
My question is now: how does this work and what’s the connection to the rotation matrix?

I am really thankful for every help!
 

Answers and Replies

  • #3
723
24
I was around the same problem but outside of course material is this correct ?

Suppose ##\psi\in C^\infty(\mathbb{R}^3,\mathbb{C})## then the rotation of coordinates should correspond to a phase : ##e^{i\phi}\psi(\vec{x})=\psi(R\vec{x})\Rightarrow \phi=i(log(\psi(\vec{x})-log(\psi(R\vec{x})))## ?

I asked myself : What about if ##\psi(\vec{x})\in \mathbb{C}^2## ?
 

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