Rotational accel to linear accel

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AI Thread Summary
The discussion focuses on solving for linear acceleration (a) of a sphere rolling down a hill using the relationship between rotational and linear motion. Key equations include the condition for rolling without slipping (alpha = a/r) and Newton's second law applied to both translation and rotation. The participant struggled with the progression of steps, particularly the integration of angular acceleration (alpha) into the equations. The final solution for linear acceleration is derived as a = (5/7)g sin theta, clarifying the confusion around combining the equations. Overall, understanding the connection between linear and rotational dynamics is essential for solving the problem.
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Homework Statement


I do not understand how a was solved for. the picture is a sphere rolling down a hill. Asked to solve for a.


Homework Equations


solve for a, use alpha = a/r
ma = mg sin theta - fs; T = fs*r = I*alpha = (2/5)mr^2; fs = (2/5)ma
a = (5/7)g sin theta

I can't see the progression through these steps

The Attempt at a Solution

 
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chloechloe said:
use alpha = a/r
(1) That's the condition for rolling without slipping.
ma = mg sin theta - fs;
(2) That's Newton's 2nd law applied to translation.
T = fs*r = I*alpha = (2/5)mr^2;
This is an attempt to apply Newton's 2nd law to rotation, but alpha was left out of the right hand term. It should be:
(3) T = fs*r = I*alpha = (2/5)mr^2*alpha
fs = (2/5)ma
(4) Combine 1 and 3 to get this.
a = (5/7)g sin theta
Combine 4 with 2 to get this.
 
Thank you. Makes sense now. I was getting stuck at combining things at the end. The missing alpha didn't help either.
 
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