1. The problem statement, all variables and given/known data (Figure is attached) A 1200.0 N uniform boom is supported by a cable,as shown in Figure 8-22.The boom is pivoted at the bot- tom,and a 2000.0 N weight hangs from its top.Find the force applied by the supporting cable and the compo- nents ofthe reaction force on the bottom ofthe boom. (See Sample Problem 8B.) Legend: t denotes torque T denotes tension d denotes distance from pivot Fg denotes gravitational force Rx denotes horizontal component of reaction force Ry denotes vertical component of reaction force. 2. Relevant equations tnet = Fd sin theta Fnet =ma 3. The attempt at a solution Take point A as pivot tnet = 0 tnet = tT + tFg1 + tFg2 = 0 +(T x 0.75L sin 90) - (Fg1 x 0.5L sin 25) - (Fg2 x L sin 25) = 0 T = 1464 N Fnet = T + Fg1 + Fg2 + Rx + Ry = 0 Fx = Fg1 cos 205 + Fg2 cos 205 + Rx = 0 Rx = 2912 N Fg = Ry + Fg1 sin 205 + Fg2 sin 205 + T sin 90 = 0 Ry = - 111 R = Sqrt(-111^2 + 2912^2) R = 2915.7 N My angles for T, Fg1, and Fg2 are 90, 205, and 205, respectively. I got this wrong, and I'm curious why.