A 36.5-cm diameter disk rotates with a constant angular acceleration of 2.00 rad/s2. It starts from rest at t = 0, and a line drawn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x-axis at this time. (a) Find the angular speed of the wheel at t = 2.30 s. (b) Find the linear velocity and tangential acceleration of P at t = 2.30 s. (c) Find the position of P (in degrees, with respect to the positive x-axis) at t = 2.30s. (a) to solve for angular speed W=at or W=(2)(2.3) and got 4.6m/s (b) first I calculated the radius by multiplying 36.5*.01 then dividing by 2 and got .1825. next I plugged it into V=(.1825)(4.6) to solve for linear velocity and got .8395. To get tangential acceleration I used A=(.1825)(2) and got .365. (c) θ=1+.5(2)(2.3)^2 and got 6.29 radians which I converted to degrees and got 360.39 and subtracted 360 to get position with respect to positive x-axis. Not sure If I did part this right can I get some verification??