A roller coaster vehicle has a mass of 500 kg when fully loaded with passengers. a) if the vehicle has a speed of 20.0 m/s at point A, what is the force of the track on the vehicle at this point (point a sits at the bottom of a drop of the roller coaster where the radius is 10 meters) B) what is the maximum speed the vehicle can have at point b for gravity to hold it on the track ( Point b sits at the top of the rollercoaster hill where the radius is 15 meters)
The Attempt at a Solution
Fc = MAc = M(v^2/r)
n=500(20^2/10)-(500x9.80) = Force of track on car at a = 15,100 N is this right?
Vtop= "square roote of" gr
="Square roote of" (9.80 x 15) = max velocity at top at point b is 12 m/s is this right?