Rotational motion, find the frictional force.

In summary, a 350-g collar C is sliding on a semicircular rod that is rotating at a constant rate of 7.5 rad/s around the vertical axis AB. The coefficients of friction are μs = 0.25 and μk = 0.20. The collar experiences two forces, rotational and gravitational, and the normal acceleration can be calculated using the equations for tangent velocity and normal acceleration. However, a computer program indicates that the solution is incorrect.
  • #1
Enginseer
2
0

Homework Statement


A small 350-g collar C can slide on a semicircular rod which is made to rotate about the vertical AB at a constant rate of 7.5 rad/s. The coefficients of friction are μs = 0.25 and μk = 0.20.
13252702377533245599.png


Homework Equations


Tangent Velocity= Radians*radius
Normal acceleration an= Vt^2/radius

The Attempt at a Solution


20150920_210516_2.jpg
 
Physics news on Phys.org
  • #2
Basically the collar has two forces acting on it. The rotational force and the gravitational force. I used the y-axis for the force components parallel/opposite to the normal force and multiplied the normal force by the kinetic friction which should have given me the frictional force. But the computer program I'm using (Mcgraw hill) says my answer is wrong.
 

1. What is rotational motion?

Rotational motion is the movement of an object around an axis or center point. It is characterized by the object's angular displacement, velocity, and acceleration.

2. How is rotational motion different from linear motion?

Rotational motion differs from linear motion in that it involves circular or curved paths, rather than straight lines. Additionally, rotational motion is described in terms of angular displacement, velocity, and acceleration, while linear motion is described in terms of distance, speed, and acceleration.

3. What is the formula for finding the frictional force in rotational motion?

The formula for finding the frictional force in rotational motion is F = μN, where F is the frictional force, μ is the coefficient of friction, and N is the normal force exerted on the object.

4. How does the coefficient of friction affect the frictional force in rotational motion?

The coefficient of friction is a measure of the roughness or smoothness of the surfaces in contact. A higher coefficient of friction will result in a greater frictional force, while a lower coefficient of friction will result in a smaller frictional force.

5. How does the normal force affect the frictional force in rotational motion?

The normal force is the force exerted on an object by the surface it is in contact with. The frictional force is directly proportional to the normal force, meaning that an increase in the normal force will result in an increase in the frictional force.

Similar threads

  • Introductory Physics Homework Help
Replies
1
Views
2K
Replies
2
Views
867
Replies
37
Views
2K
Replies
11
Views
939
Replies
22
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
16
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
6
Views
4K
  • Engineering and Comp Sci Homework Help
Replies
5
Views
3K
Back
Top