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ball has a radius of 2.5 cm a mass of .125 and is rolling across a table with a speed of .547 m/s, this table is 1.04 m off the ground. It rolls to the edge and down a ramp How fast will it be rolling across the floor?

First I found theGravitational Potential Energy: Ep=mgh

Initial of 1.2753 FInal = 0

THen theLinear Kinetic ENergy: 1/2 mv^2

Initial .0187005625 FInal .0625v^2

Elastic Potential Energy: .5k(delta)x^2

0 0

Rotational Kinetic Energy: 1/5mv^2

initial .007480225 FInal .025v^2

Now I need to bring them all togther and solve the final velocity.

Is the Sum of the inital energy's = to the SUM of the final energy's?

If that's true then 1.30148075 = .0875v^2

so v = 3.85 m/s

Is that at all right??

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# Homework Help: Rotational Motion FInding the total ENergy

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