Rotational Motion (thin hollow pipe)

AI Thread Summary
The discussion revolves around a physics problem involving a thin hollow pipe rolling down an incline. The user successfully calculated the speed at the base of the incline as 4.06 m/s and the total kinetic energy as 0.989 J. However, they are struggling with determining the minimum coefficient of static friction required to prevent slipping. Suggestions include drawing a force diagram and applying Newton's second law along with torque equations. The conversation emphasizes the importance of understanding the forces and torques acting on the pipe.
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Homework Statement


thin, hollow 60.0 g section of pipe of radius 14.0 cm starts rolling (from rest) down a 17.5° incline 5.60 m long.
(a) If the pipe rolls without slipping, what will be its speed at the base of the incline?
(b) What will be its total kinetic energy at the base of the incline?
(c) What minimum value must the coefficient of static friction have if the pipe is not to slip?


Homework Equations





The Attempt at a Solution


I got a) V=sqrt(gh) V=4.06m/s and b) KE=mv^2=mgh KE=0.989J which are correct.
c) I need help with this one, I am not sure where to begin.
 
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This is a tricky question.

Without thinking this through completely, I'll suggest drawing a force diagram for the piple, including friction. Then some equations involving Newton's 2nd Law, and the torque-rotation version of Newton's 2nd Law.
 

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