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"One end of a uniform meter stick is placed against a vertical wall View Figure . The other end is held by a lightweight cord that makes an angle [itex]\theta[/itex] with the stick. The coefficient of static friction between the end of the meter stick and the wall is 0.400 ."

I can't for the life of me get the equation for this.

Part A:

What is the maximum value the angle [itex]\theta[/itex] can have if the stick is to remain in equilibrium?

So far I've tried using the last end as a pivot point.

so that would give me

Balancing torque:

[tex]\mu T cos(\theta) = mg(1-x)[/tex]

and balancing total forces

[tex]\mu T cos(\theta) + T sin(\theta) = mg [/tex]

combining the two

produces

[tex] T sin(\theta) = mgx[/tex]

dividing the third by the first gives me

[tex] tan(\theta) = \mu \frac{x}{1-x} [/tex]

and there is no way I can get a "max theta". Naturally I can't get Part B and C but I figured if you guys can help me with A it will be easy to get the rest.

Thanks in advanced.

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# Homework Help: Rotational Statics problem

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