(2)(9.8)(sin41) is correct for the component of gravity down the incline, but (.27)(2)(9.8) is not correct for the friction force. (Remember that [itex]F_f = \mu N[/itex].)Alt+F4 said:
That's all there is to it. The hanging mass exerts a counter-clockwise torque on the cylinder; the force on the handle exerts a clockwise torque. These must be equal (and opposite) for rotational equilibrium.Alt+F4 said:
What you're doing wrong is jumping the gun and not reading the question. You immediately went to solve for the support force, but that was not the question.Alt+F4 said:
Yes, that's how it's done.Alt+F4 said:
Thanks. Okay so 3 forces acting on car, Inward Centripital, normal and Gravity. Centripetal Acc = 7.5 m/s^2 how do i find friction thanks"centripetal" is a direction, not a kind of force. The three forces are: friction, normal force (what is that?), and weight.Alt+F4 said:http://online.physics.uiuc.edu/cgi/courses/shell/phys101/spring06/prep2a.pl?practice/exam1/sp05 Question 19. My exam is in 2 hrs so can i have strong hints.
Hint: What must be the same about the two wheels, since the belt doesn't slip?Alt+F4 said:
ooo man i am so stupid. I wish i had hints like these durin exams hahaa i was making it more complicated than it is. thanksDoc Al said:
You have all the info needed to figure out [itex]T_1[/itex] & [itex]T_2[/itex].Alt+F4 said:
I assume you're talking about problem 4. Don't confuse force with torque. Hints: What is [itex]\alpha[/itex]? (Key: rolling without slipping.) What force produces the torque about the center of mass?Alt+F4 said:
One way to solve this is to use conservation of energy. Hint: Realize that the cylinder will have both rotational and translational KE. (The two are related, since it rolls without slipping.)
thanks for all ur help