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Rubik cube

  1. Feb 14, 2005 #1
    Dear friends,

    I need some help with this problem.
    "What is the probability of building a solvable rubik cube only by ordering randomly all pieces but three"(let us suposse that these 3 pieces are vertices)
    That is you first get a random cube without three vertices and then you try to build a solvable cube by choosing a correct position for these three vertices.

    What I got is that only 1/12 of all posible random cubes are solvable. I think that all posible random configurations are 8!*3^8*12!*2^8. But the thing is that in this problem 3 vertices are correctly places. I don't know what to do.

    Thanks for your help
  2. jcsd
  3. Feb 15, 2005 #2
    just a hint, please
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