Run Fastest to Weigh Most at Equator!

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To weigh the most while running at the equator, one must consider the effects of centrifugal force due to the Earth's rotation. Gravitational acceleration is slightly lower at the equator (9.78 m/s²) compared to the poles (9.83 m/s²), resulting in a weight difference. The net force acting on a person running at the equator is influenced by this centrifugal effect, which can be minimized by running in the direction opposite to the Earth's rotation. While the gravitational force is nearly equal at both locations, the apparent weight is affected by the Earth's shape and rotation. Understanding these dynamics is crucial for determining how speed impacts weight at the equator.
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Homework Statement


What speed you have to run on the equator to weigh as much as possible (the greatest weight) if you do
choose the right direction? Do not consider relativity.

Homework Equations


ravitational acceleration is 9.78 m/s2 at the equator and 9.83 m/s2 at the poles, so you weigh about 0.5% more at the poles than at the equator.

The Attempt at a Solution


Absolutely don't know :D
 
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Johny158 said:
ravitational acceleration is 9.78 m/s2 at the equator and 9.83 m/s2 at the poles, so you weigh about 0.5% more at the poles than at the equator.

That's not really relevant to this question. This isn't about the difference between the poles and equator.

Sorry I should correct my initial reply. Gravitational force is actually about the same at the equator and the poles. The net force acting on you is different at the equator and poles.

Hint: It's about an effect that occurs at all latitudes except the poles and how you could reduce this effect?

Hintt 2: The Earth isn't a perfect sphere. Why?
 
CWatters said:
Gravitational force is actually about the same at the equator and the poles.
Well, it is about 0.2% less at the equator, but as you say the apparent gravitational force (the ratio between weight and mass) is about 0.5% less.
 
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