Sail Boat Race Trigonometry, just stuck on first part

AI Thread Summary
The discussion focuses on solving a sailboat race trigonometry problem involving displacement vectors A, B, C, and D. The angles and magnitudes of the vectors are provided, with an emphasis on breaking them into x and y components. The initial calculations for vector D were incorrect due to miscalculating the components and not properly accounting for the direction of vector B and C. The correct approach involves subtracting the components of vectors B and C from A when calculating D's components. The final magnitude of vector D is determined to be 4.53 km, correcting the initial erroneous calculation of 13.70 km.
Juntao
Messages
45
Reaction score
0
I've added a picture that's part of the problem.

A sailboat race course consists of four legs defined by the displacement vectors A, B, C and D shown above.
The values of the angles are È1 = 420, È2 = 410, and È3 = 270.

The magnitudes of the first three vectors are A = 3.7 km, B = 5.3 km and C = 4.8 km. The finish line of the course coincides with the starting line.

The coordinate system for this problem has positive x to the right, positive y as up and counter-clockwise to be a positive angle.

------------------------------------------------------------------
Now first thing I should do is break up each vector into its components, and then add up all the x and y components to get vector D.

This is what I've tried.

Vector a
x-component = 3.7*cos 42=2.75km
y-component = 3.7*cos42= 2.48km

vector b
x component = 5.3*cos 41=4.00km
y component = 5.3*sin41= 3.48km

vector c
x component = 4.8*cos 27=4.27km
y component= 4.8*sin27= 2.18km
-------------------------------------------------------------------
vctor d
x component = 11.02km
y component = 8.14km

So for vector d, just add up the first 3 components in their respective columns. However, when I calculate D's distance => sqrt(11.02^2+8.14^2), I get the incorrect answer of 13.70km.
So of course, if this answer is wrong, then most likely I figured out one of the components wrong, but I don't know which ones. Please help.
 

Attachments

  • vectors.gif
    vectors.gif
    1.8 KB · Views: 1,126
Last edited:
Physics news on Phys.org
Did you notice that vector B is going back to the LEFT? Its x component is negative. Both the x component and y component of C will be negative. Also notice that once you have added the components of A, B, and C, the result will be the NEGATIVE of D.
 
Last edited by a moderator:


It looks like you have correctly calculated the x and y components for vectors A, B, and C. However, when adding them together to find the x and y components for vector D, it seems that you have added the y components instead of subtracting them.

The correct way to find the x and y components for vector D would be:

x component = 2.75 km + 4.00 km - 4.27 km = 2.48 km
y component = 2.48 km + 3.48 km - 2.18 km = 3.78 km

Then, using the Pythagorean theorem to find the magnitude of vector D, we get:

D = sqrt(2.48^2 + 3.78^2) = 4.53 km

So the correct answer for the distance of vector D would be 4.53 km, not 13.70 km.

I hope this helps clarify the mistake and helps you solve the rest of the problem. Remember to always double check your calculations and make sure you are adding and subtracting the correct components. Good luck!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top