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In page 26 of 'Modern Quantum Mechanics (Revised edition)' by J.J. Sakurai, equation (1.4.9), they find the S_x + ket,
\mid S_x;+ \rangle = \frac{1}{\sqrt{2}} \mid + \rangle + \frac{1}{\sqrt{2}} e^{i \delta_1} \mid - \rangle with \delta_1 real. What is this \delta_1?
Furthermore, equation (1.4.8) says,
| \langle + \mid S_x ; + \rangle | = | \langle - \mid S_x ; + \rangle | = \frac{1}{\sqrt{2}}
But if you take equation(1.4.9) and apply \langle - \mid to it from the left, it becomes,
\langle - \mid S_x ; + \rangle = \frac{1}{\sqrt{2}} e^{i \delta_1}
This does not match with equation (1.4.8). There's this extra factor of e^{i \delta_1}
Could someone help me with this? Thanks a lot.
\mid S_x;+ \rangle = \frac{1}{\sqrt{2}} \mid + \rangle + \frac{1}{\sqrt{2}} e^{i \delta_1} \mid - \rangle with \delta_1 real. What is this \delta_1?
Furthermore, equation (1.4.8) says,
| \langle + \mid S_x ; + \rangle | = | \langle - \mid S_x ; + \rangle | = \frac{1}{\sqrt{2}}
But if you take equation(1.4.9) and apply \langle - \mid to it from the left, it becomes,
\langle - \mid S_x ; + \rangle = \frac{1}{\sqrt{2}} e^{i \delta_1}
This does not match with equation (1.4.8). There's this extra factor of e^{i \delta_1}
Could someone help me with this? Thanks a lot.