Satellite Control System With Rate Feedback

  • Thread starter jj007
  • Start date
  • #1
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I'm trying to get the transfer function of this rigid control system that uses rate feedback to stabilize it. Using k=1 and kv=0
Capture_zps6fbe8d62.png


Attempt at a solution.
When kv=0, the rate feedback is removed.
In the block diagram, I moved the pickoff point and used the cascade rule to get [tex] 1/s^2 [/tex]
and the transfer function for the top portion is [tex] H(s)=\frac{(1/s^2)k}{1+(1/s^2)k}=\frac{k}{s^2((k/s^2)+1)}[/tex]
With the pickoff point moved you get [tex]\frac{1}{1/s}[/tex] at the bottom next to kv.
This is where I'm stuck. How do I get the complete transfer function? I would like to put it in matlab.

Thanks
 

Answers and Replies

  • #2
818
67
This looks like something you probably should have posted in the Homework section, just FYI.

What transfer function is it you want? Is it θ(s)/θ_r(s)?
 
  • #3
8
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This looks like something you probably should have posted in the Homework section, just FYI.

What transfer function is it you want? Is it θ(s)/θ_r(s)?
Yes please.
 
  • #4
berkeman
Mentor
57,939
8,007
(thread moved to HH)
 
  • #5
818
67
For K = 1, K_v = 0, you have a double integrator, 1/s^2, in a unity feedback configuration and the transfer function you posted, H(s), is the closed-loop transfer function θ(s)/θ_r(s) for this system.

In case you're looking for θ(s)/θ_r(s) with K, K_v only known to be real, you could apply block simplification for the inner loop first, then the outer one using the rule for negative feedback loops. You already used this rule once in finding H(s).
 
  • #6
8
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That's the only thing I'm not sure of...the block simplification. There's so many rules and I don't know which ones to apply here.
 
  • #7
818
67
This was the first link on Google for 'block simplification':
http://www.msubbu.in/sp/ctrl/BD-Rules.htm

Have a look at rule 1, 2 and 6. Try simplifying your block diagram to a single system using those rules and post here if you get stuck.
 
  • #9
818
67
Split up the summing junction and simplify the series inside the inner loop, rule 1 & 2:

sys1.jpg


Simplify the inner negative feedback loop, rule 6:

sys2.jpg


Do you understand those steps? How would you proceed?
 
  • #10
8
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Split up the summing junction and simplify the series inside the inner loop, rule 1 & 2:

sys1.jpg


Simplify the inner negative feedback loop, rule 6:

sys2.jpg


Do you understand those steps? How would you proceed?
Understood. Proceed by using rule 2 again and that's it? Looks like I was over complicating things.

Thanks
 
  • #11
818
67
Rule 2 to simplify the series inside the loop, but what about the loop itself?
 
  • #12
8
0
Rule 2 to simplify the series inside the loop, but what about the loop itself?
The output [itex]\theta[/itex] goes back into junction, which gives a transfer function of 1?
We're looking for [itex]\frac{θ(s)}{θ_r(s)}[/itex] right?
 
  • #13
818
67
We want to simplify the block diagram so it looks like:

θ_r -> box -> θ

and nothing else. No loops!

Have a look at the step I did using rule 6. Doesn't that look like something you could do again?
 
  • #14
8
0
Y=[itex]\frac{G1}{1+G1(1)}[/itex]= [itex]\frac{K}{s^2+s*K*K_v+K}[/itex]?
 
  • #16
8
0
Ok. Last Question. For K=1 and K_v=0, how do I use this transfer function in matlab to get the Root Locus or Bode plot?
 
  • #17
818
67
Ok. Last Question. For K=1 and K_v=0, how do I use this transfer function in matlab to get the Root Locus or Bode plot?
If you have the Control System Toolbox you could use its suite of commands, e.g.:
tf
bode
rlocus

and so on. Have a look at their help pages and that of the toolbox itself.

If you don't have it, you could make your own functions to evaluate the transfer function for whatever range of parameters you're interested in and plot the results.
 
  • #18
jhae2.718
Gold Member
1,161
20
There is an rlocus function in MATLAB that will plot the root locus plot of a given transfer function.
 

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