Satellite Orbit Problem what am I doing wrong?

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Homework Help Overview

The discussion revolves around a satellite orbit problem involving a spacecraft in a low circular orbit around the moon. The problem includes parameters such as the moon's diameter and the free-fall acceleration at its surface, with the goal of determining the spacecraft's orbital speed.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the orbital speed using gravitational equations, specifically v = √(G * M / R) and mg = mv²/R. They express confusion over receiving incorrect results despite following these equations.

Discussion Status

Participants are actively engaging in the discussion, with some providing feedback on unit conversions and the correct application of gravitational constants. There is an ongoing exploration of the original poster's calculations and potential misunderstandings regarding units.

Contextual Notes

There is a noted concern about unit consistency, particularly between kilometers and meters, as well as the proper use of gravitational constants in calculations. The original poster's calculations are questioned, indicating a need for clarity on these aspects.

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I have a satellite orbit problem I'm not quite understanding...any help would be appreciated.

Homework Statement



Suppose a spacecraft orbits the moon in a very low, circular orbit, just a few hundred meters above the lunar surface. The moon has a diameter of 3500 km, and the free-fall acceleration at the surface is 1.60 m/s^2.

Homework Equations



1. How fast is this spacecraft moving?

The Attempt at a Solution



To find the speed, I used the equation v= square root of (G X M/R), with M being the mass of the moon (I had to look that up) and G being the gravitational constant.

v= square root of (6.674E-11)(7.36E22/1750)=52980.125=>52.9 m/s

The answer I got was an available option under the answer choices; however, I got it wrong. I can't figure out another way to come up with the velocity.

I also tried using the equation mg=mv^2/R; however, I got the same number as before.
m's cancel;
g=v^2/R
v= square root of g*R
Acceleration = g in freefall
V = square root of 1.60*1750km=>52.9 m/s

Both of these answers are incorrect. What am I doing wrong?
 
Last edited:
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Watch your units! Kilometers and meters are not the same.
 
Didn't I convert between them? For the first equation I used, 52980.125 is in kilometers, then I moved the decimals 3 places over to convert to meters.
 
No, it is not. It is in goofy units. G is not just a number, and you used it is such. It has units. You used G=6.674E-11, more correctly, G=6.674×10-11 m3 kg-1 s-2.
 

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