Satellite velocity and momentum

AI Thread Summary
A satellite in a circular orbit of radius r has a speed calculated using the formula v = sqrt(GM/r). After an explosion, the satellite splits into two pieces, with the smaller mass m stationary and the larger mass 4m gaining speed. The momentum conservation equation indicates that the speed of the larger piece immediately after the explosion is vi = (5/4)vo. To determine the new elliptical orbit of the larger piece, the total energy before and after the explosion must be compared, leading to the expression for its new distance from the center of the Earth. The discussion emphasizes using energy and momentum conservation principles to solve the problem.
jlayla99
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Homework Statement


A satellite moves around the Earth in a circular orbit of radius r.
a) What is the speed vo of the satellite?
Suddenly an explosion breaks the satellite into two pieces, with masses m and 4m. Immediately after the explosion the smaller piece of mass m is stationary with respect to the Earth and falls directly toward the Earth.
b)What is the speed vi of the larger piece immediately after the explosion?
c) Because of the increase in its speed this larger piece now moves in a new elliptical orbit. Find its distance away from the center of the Earth when it reaches the other end of the ellipse.


Homework Equations


K=.5mv^2
E=-GMm/2r
mv=mv
E=-GMm/2a



The Attempt at a Solution


a) I think I got the answer to a:
.5mv^2=GMm/2r
v=sqrt(GM/r)
Then substituting in the values of G and M (Mass of the Earth):
v=1.99x10^7/sqrt(r)

b) I am having trouble with this because I don't know if I can simply use linear momentum. If so then I can just assume that the smaller mass has no momentum in relation to the first.
mv=mv
5m(vo)=4m(vi)
(5/4)vo=vi
Is it really that simple?

c) I'm kind of shooting in the dark with this one, but can I assume that the energy initially (GM(5m)/2r) is going to equal the second energy (GM(4m)/2a?
 
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jlayla99 said:
a) I think I got the answer to a:
.5mv^2=GMm/2r
v=sqrt(GM/r)
Then substituting in the values of G and M (Mass of the Earth):
v=1.99x10^7/sqrt(r)
OK, but I wouldn't bother plugging in numerical values. Leave your answer in terms of G, M, and r.

b) I am having trouble with this because I don't know if I can simply use linear momentum. If so then I can just assume that the smaller mass has no momentum in relation to the first.
mv=mv
5m(vo)=4m(vi)
(5/4)vo=vi
Is it really that simple?
Yes, that simple.

c) I'm kind of shooting in the dark with this one, but can I assume that the energy initially (GM(5m)/2r) is going to equal the second energy (GM(4m)/2a?
Compare the energy of the masses before and after the explosion.
 
what do you mean compare the energies?
the energy before: .5m(vo)^2 - GM(5m)/2r
the energy after: .5m(vi)^2 - GM(4m)/2a

where do i go from there?
 
Express the total energy immediately after the explosion in terms of the energy before the collision. Then use that new energy to solve for length of the new orbit.
 
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