Satisfying Dirac equation, how to make equal to zero.

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SUMMARY

The discussion centers on solving the Dirac equation, specifically the expression $$(\gamma ^{\mu}\rho_{\mu}-mc)\psi=0$$. The user attempts to simplify the equation and realizes that when the particle is at rest, all ##\rho## components are zero, leading to the conclusion that the term $E/c - mc$ must equal zero. This is confirmed by the relationship $E=mc^2$, establishing that the energy of a particle at rest is directly proportional to its mass.

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rwooduk
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Homework Statement


AZGM7km.jpg


Homework Equations


Dirac equation: $$(\gamma ^{\mu}\rho_{\mu}-mc)\psi=0$$

The Attempt at a Solution


If we multiply out the Dirac equation by inserting all it's components we get:

a8n4gLY.jpg


which if I've multiplied it correctly gives $$
\begin{bmatrix}
\frac{E}{c}-mc\\ 0
\\ \rho_{z}
\\ \rho_{x}+i\rho_{y}

\end{bmatrix}e^{-\frac{iEt}{\hbar}}=0$$

I'm not sure how to show the left hand side is equal to zero?

edit just realized that it is at rest so all the ##\rho## components would be zero, but then I still don't see how E/c - mc multiplied by the exponential would give zero?

Any help / ideas would really be appreciated.
 
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If the particle is at rest, what is its relation between energy and mass?
 
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mfb said:
If the particle is at rest, what is its relation between energy and mass?

ahhhh E=mc^2 so the term in the matrix would be zero, many thanks!
 

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