Satisfying trig equations between (0,2pi)

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Homework Statement


cos^2 x-cos x- 1= 0


Homework Equations


several trig identities involving cos


The Attempt at a Solution


i tried applying identites everywhere, no luck. I've tried using it as a trinomial...no luck...and I've tried adding one to both sides and still no luck...please help lol
 
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banfill_89 said:

Homework Statement


cos^2 x-cos x- 1= 0


Homework Equations


several trig identities involving cos


The Attempt at a Solution


i tried applying identites everywhere, no luck. I've tried using it as a trinomial...no luck...and I've tried adding one to both sides and still no luck...please help lol

If you squint your eyes a bit, you might notice that this is a quadratic in cos x. Think about how you would solve x^2 - x - 1 = 0, but keep in mind that you're solving for the cosine of x, not x.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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