Scaling factor of Energy in a capacitor with change in charge

AI Thread Summary
The discussion centers on the relationship between charge, voltage, and energy in a capacitor. When the charge (Q) increases by 1.5 times while capacitance (C) remains constant, the voltage (V) must also increase by 1.5 times. Consequently, the energy (E) stored in the capacitor, calculated using E = 0.5QV, increases to 2.25 times its original value. Participants confirm that the logic and method used in the calculations are correct. The discussion emphasizes the fundamental equations governing energy storage in capacitors.
mrcotton
Messages
120
Reaction score
0

Homework Statement


AQA Section A Q18 Jun 11
photbucket3_zps580de911.jpg


Homework Equations



The answer should be C

E=.5QV and C=Q/V

The Attempt at a Solution



So the original Q has increased by 1.5 times If C is constant than the voltage must also increase by 1.5 times

Now the energy E is E=.5QV V has increase by 1.5 and and so has Q which is 2.25

Infact in typing this out I think I just solved it. Is this logic and method ok
 
Physics news on Phys.org
mrcotton said:

Homework Statement


AQA Section A Q18 Jun 11
photbucket3_zps580de911.jpg


Homework Equations



The answer should be C

E=.5QV and C=Q/V

The Attempt at a Solution



So the original Q has increased by 1.5 times If C is constant than the voltage must also increase by 1.5 times

Now the energy E is E=.5QV V has increase by 1.5 and and so has Q which is 2.25

Infact in typing this out I think I just solved it. Is this logic and method ok

Seems fine to me.
 
Yup. You may recall that the energy stored in a capacitor is also given by:


E = \frac{1}{2}CV^2
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top