lugita15 said:
A linear functional is a linear mapping from a vector space to the real line, and a bilinear functional is a linear mapping from the Cartesian product of a vector space and itself to the real line.
OK, that's reasonably close. The actual definitions are a little more general, cf.
http://en.wikipedia.org/wiki/Bilinear_functional
Also, for QM we usually take the range to be the complex plane rather than just the real line.
A rigged Hilbert space arises from the Gelfand triplet consisting of a Hilbert space, a nuclear subspace on which unbounded Hilbert space operators are defined, and a space of anti-linear functionals, essentially Schwartz distributions except for the anti-linear part, using the nuclear subspace as the set of test functions on which the functionals act.
The case of Schwartz test functions and tempered distributions is a special case. But ok, that's enough to go on with...
[...] I often [...] just refer to the ket space, i.e. the space of anti-linear functionals, out of this triplet as the "Rigged Hilbert Space".
IMHO, that's actually a reasonable complaint. There's no overarching term for the whole thing, afaik. Maybe it deserves to be called a "Dirac space", since it was his approach to QM that motivated much of the rigorous development. :-)
Where can I find more information about constructing a two-dimensional delta function as a family of delta functions? Would it be there in Gelfand?
It depends what you mean by "two-dimensional delta function". I interpret it to mean a
bilinear functional ##\delta_{pq},~ p,q \in \mathbb{C}##, acting on some vector space ##\mathbb{F}## of functions over ##\mathbb{C}^2##, and defined via
$$
\def\Cz{\mathbb{C}}
\def\Fz{\mathbb{F}}
\Big( \delta_{pq} \,,\, f \Big) ~=~ f(p,q)
$$
Normally, we'd like to write the above as
$$
\int dx \delta(p-x) \int dy \, \delta(q-y) \; f(x,y) ~=~ f(p,q) ~.
$$
But now consider an
arbitrary bilinear functional K satisfying
$$
\Big( K \,,\, f \Big) ~=~ z_f
$$
where ##z_f## is a family of complex numbers dependent on the function f.
The Schwartz kernel theorem (iiuc!) states that one can always express ##K##
and its action in the form
$$
\int dx \int dy \, K(x,y) \; f(x,y) ~=~ z_f ~.
$$
That's why it's called the "kernel" theorem. The quantity ##K(x,y)## is the "integral kernel" defining the bilinear functional.
Depending on the details of K, it may or may not be possible to express it as a simple product ##A(x)Y(y)## as we did for the 2D delta distribution.
So maybe you can now re-study the sections in G+V on the kernel theorem, and you (or anyone else -- please!) can tell me whether I've got it right... :-)