Second moment of area of a hollow triangle

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To calculate the second moment of area for a hollow isosceles triangle, one can use the subtractive method by calculating the moments of the larger and smaller triangles separately. However, this method requires determining the centroid of the hollow shape, as the centroids of the two triangles do not share a common axis. The parallel axis theorem must be applied to account for this difference in centroid locations. Additionally, consideration must be given to the thickness of the base wall compared to the sides. Accurate calculations will ensure a correct assessment of the area moment of inertia about the centroid.
Becky6
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Greetings!
Can someone please help me figure out how to calculate the second moment of area for a hollow isosceles triangle? Is there an equation available somewhere? Or can I simply subtract a smaller triangle from a larger one, using the equation I=bh3/36? (so I= b1h13/36 -b2h23/36)

Also, is there any way to account for the base wall being thicker than the sides?

Thank you!
 
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Presumably you are looking for the area moment of inertia about the centroid of the hollow triangle. The subtractive method is ok. But it's not as simple as you indicate, because the centroid of each triangle do not share a common axis. You must first determine the centroid location of the hollow shape, then calculate the inertia of that shape using parallel axis theorem.
 
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