Second order differential equation

  • Thread starter eidbadr
  • Start date
  • #1
2
0
hello i need some help here!

solve:

x''+3x'+2x=1/(1+e^t)

well ok the homogeneous solution is c1*e^t+c2*e^2t
but how to determine the particular solution Xp!!!!!
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,223
31
Try using the variation of parameters method
 
  • #3
HallsofIvy
Science Advisor
Homework Helper
41,847
965
If the right hand side were a function of the kind one gets as a solution to a "homogenoous linear equation with constant coefficients"- polynomial, exponentian, sine and cosine, or combinations of those- then you could try "undetermined coefficients' but since it is not you will need to try "variation of parameters" as rock.freak667 suggested.
 
  • #4
2
0
thanks that worked,

if you could give me a hint for this one

t*x'=x+sqrt(x^2-t^2)
 

Related Threads on Second order differential equation

  • Last Post
Replies
1
Views
491
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
740
  • Last Post
Replies
3
Views
993
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
1
Views
735
  • Last Post
Replies
5
Views
926
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
1
Views
963
  • Last Post
Replies
5
Views
3K
Top