Second order frequency response question

AI Thread Summary
The discussion revolves around finding an equivalent parallel circuit for an RLC circuit, specifically addressing confusion in the first part of the problem. The initial approach involves combining the capacitor, inductor, and resistances into a series circuit before attempting to split the impedance into parallel components. There is uncertainty about the mathematical process for this impedance splitting, and alternative methods like using Thevenin or Norton equivalents are suggested. Participants are exploring whether a simpler or more elegant solution exists for the problem. The conversation emphasizes the complexity of transforming the circuit while seeking clarity on the impedance relationships.
Learnphysics
Messages
92
Reaction score
0

Homework Statement


http://img534.imageshack.us/img534/9687/rlc.png

Cannot do this question, the first part confuses me when it asks to find an equivalent Parallel circuit.

My first instinct was to try to add the capacitor and inductor and 40k Resistance together to create an RLC series circuit.

From this to add the 40k and the 10k resistances (because they are now in series)... Then we have a circuit with one resistance and one component causing impedance.

From here if we could SPLIT the impedance into both capacitance and inductance, we would have a parallel RLC.



how to mathamatically do the last part (the splitting of a given impedance into a parallel capacitance and inductance) I have no idea.

Or is there a much more simple/elegant way to go about doing this?
 
Last edited by a moderator:
Physics news on Phys.org
Have you tried Thevenin equivalent?
 
Learnphysics said:

Homework Statement



Cannot do this question, the first part confuses me when it asks to find an equivalent Parallel circuit.

My first instinct was to try to add the capacitor and inductor and 40k Resistance together to create an RLC series circuit.

From this to add the 40k and the 10k resistances (because they are now in series)... Then we have a circuit with one resistance and one component causing impedance.

From here if we could SPLIT the impedance into both capacitance and inductance, we would have a parallel RLC.
how to mathamatically do the last part (the splitting of a given impedance into a parallel capacitance and inductance) I have no idea.

Or is there a much more simple/elegant way to go about doing this?

I'm not 100% sure about this but couldn't you simply find the Norton equivalent at the terminals of the inductor?

Then you would have a parallel RLC circuit with a current source supplying power as opposed to a voltage source.
 

Similar threads

Replies
17
Views
6K
Replies
21
Views
1K
Replies
11
Views
5K
Replies
1
Views
1K
Replies
26
Views
3K
Back
Top