Second order linear system and power series: Differential Equations

clarineterr
Messages
12
Reaction score
0

Homework Statement


Find a third degree polynomial approximation for the general solution to the differential equation:

\frac{d^{2}y}{dt^{2}} +3\frac{dy}{dt}+2y= ln(t+1)

Homework Equations


Power series expansion for ln(t+1)


The Attempt at a Solution



The system to the corresponding homogeneous equation \frac{d^{2}y}{dt^{2}} +3\frac{dy}{dt}+2y = 0

is y(t) = k1e-t +k2e-2t

Then I guessed\frac{ at^{3}}{3}-\frac{bt^{2}}{2}+ct as a solution for the original equation. Plugging this in I got a=1/2, b=2,c=2/3

But then I still have the t^{4}, t^{5} terms, etc left in the equation. I am not quite sure how a third degree polynomial can be a solution to this equation.
 
Physics news on Phys.org
clarineterr said:
I am not quite sure how a third degree polynomial can be a solution to this equation.
Because it will be an approximation not really the solution itself.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top