Second order linear system and power series: Differential Equations

clarineterr
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Homework Statement


Find a third degree polynomial approximation for the general solution to the differential equation:

\frac{d^{2}y}{dt^{2}} +3\frac{dy}{dt}+2y= ln(t+1)

Homework Equations


Power series expansion for ln(t+1)


The Attempt at a Solution



The system to the corresponding homogeneous equation \frac{d^{2}y}{dt^{2}} +3\frac{dy}{dt}+2y = 0

is y(t) = k1e-t +k2e-2t

Then I guessed\frac{ at^{3}}{3}-\frac{bt^{2}}{2}+ct as a solution for the original equation. Plugging this in I got a=1/2, b=2,c=2/3

But then I still have the t^{4}, t^{5} terms, etc left in the equation. I am not quite sure how a third degree polynomial can be a solution to this equation.
 
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clarineterr said:
I am not quite sure how a third degree polynomial can be a solution to this equation.
Because it will be an approximation not really the solution itself.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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