Sending a sound wave of 1cm wavelength through a 0.1Pascal medium

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SUMMARY

This discussion focuses on the behavior of sound waves, specifically a sound wave with a 1 cm wavelength traveling through a medium with a pressure of 0.1 Pascal. The radius of the oxygen molecule is estimated to be approximately 1.5 x 10-10 m. The conversation highlights the confusion regarding the relationship between wavelength and mean free path, suggesting that the mean free path may increase by a factor of 10 due to the wavelength being 1 cm while the mean free path is 10 cm. Additionally, the dynamics of molecules in a standing wave are explored, particularly their behavior at nodes.

PREREQUISITES
  • Understanding of sound wave properties, including wavelength and frequency
  • Knowledge of molecular physics, specifically mean free path concepts
  • Familiarity with standing wave phenomena in physics
  • Basic grasp of pressure variations in gases
NEXT STEPS
  • Research the principles of sound wave propagation in different media
  • Study the concept of mean free path in gases and its implications on sound transmission
  • Explore the characteristics of standing waves and their impact on molecular motion
  • Investigate pressure variations and displacement in sound waves at nodes and antinodes
USEFUL FOR

Students and professionals in physics, particularly those studying acoustics, molecular dynamics, and wave mechanics, will benefit from this discussion.

PhysicsKush
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Homework Statement
At what pressure (at room temperature) would the mean free path of air molecules reach a macroscopic scale like ##10## cm ? Explain (qualitatively) what would happen if we tried to propagate a sound wave of wavelength ##1## cm in these conditions.
Relevant Equations
$$ l \approx \frac{1}{4 \pi r^{2}}\frac{kT}{p}, $$
I answered the first part of the question where I estimate the radius of ##O_{2}## is ##\approx 1.5 \times 10^{-10} \ \text{m}##:
$$ p = \frac{KT}{l 4 \pi r^{2}} = \frac{(20+273.15)(1.38\times 10^{-23})}{(0.1)(4\pi)(1.5 \times 10^{-10})^{2}} = 0.143 \ \text{Pa}.$$

The confusion arises on the second part of the question. Intuitively I'm thinking that a wave sent through a medium compresses and decompresses periodically the molecules it goes through. If the wavelength is ##1##cm and the mean free path is ##10##cm , then I believe the mean free path will increase by a factor of ##10##? I'm not sure what to think of this problem. Any insights would be appreciated.
 
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Consider a standing wave. Between two nodes, the molecules are bouncing back and forth. What are they bouncing off?
 
haruspex said:
Consider a standing wave. Between two nodes, the molecules are bouncing back and forth. What are they bouncing off?
Sorry , I am not sure to understand the setup. Are they just bouncing off the nodes?
 
Mihail Anghelici said:
Sorry , I am not sure to understand the setup. Are they just bouncing off the nodes?
In a standing sound wave, what is happening at a node in terms of pressure variation and displacement?
 

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