What Is the Nth Term of the Sequence 2, -5, 10, -17?

AI Thread Summary
The discussion revolves around finding the nth term of the sequence 2, -5, 10, -17. Participants analyze various proposed formulas, with one suggesting the formula (n) + (2n-1)(-1)^(n-1), which is later criticized for being incorrect beyond the first term. Another participant proposes that the correct nth term is 1 + n^2, but acknowledges that their initial answer was only accurate for the first two terms. The conversation highlights the need for a formula that consistently applies to all terms in the sequence, with a focus on the alternating signs and the pattern of increases. Ultimately, the search for a valid nth term continues amidst corrections and clarifications.
dtl42
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This was the extra credit question on a quiz I had today, I am very anxious to find out the answer.


1. Homework Statement

Find the apparent Nth term of the sequence
2,-5,10,-17 ... n



2. Homework Equations

Not sure really on this
an = ...


3. The Attempt at a Solution

(n)+(2n-1)*(-1)^(n-1)

The sequence starts with 2 and then increases by sequential odd numbers and alternates positive and negative.


Thanks very much
 
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As far as I can tell, your answer is correct. Nice Job!
 
Actually I was thinking about it and my answer is only correct for the first two terms, after that it's in accurate, the real answer is

1+n^2 , I'm hoping that my teacher is swamped with grading and will only check the first two terms.
 
dtl42 said:
Actually I was thinking about it and my answer is only correct for the first two terms, after that it's in accurate, the real answer is

1+n^2 , I'm hoping that my teacher is swamped with grading and will only check the first two terms.

you forgot the (-1)^(n-1) part.
And your original answer does not wort even for the first two terms, just for the first one.

when u take n=2 you will get

2+(4-1)(-1)^1=2-3=-1
 
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It looks to me like the nth term is the sum of the first n primes times (-1 raised to the power of n+1)
 
sutupidmath said:
you forgot the (-1)^(n-1) part.
And your original answer does not wort even for the first two terms, just for the first one.

when u take n=2 you will get

2+(4-1)(-1)^1=2-3=-1

Im positive my answer works for the first two

(2+(4-1)) * (-1)^(2-1) = -5
 
dtl42 said:
Im positive my answer works for the first two

(2+(4-1)) * (-1)^(2-1) = -5

But that's not what you wrote! In your first post you wrote
(n)+(2n-1)*(-1)^(n-1) where the (-1)^(n-1) is multiplied only by the second term, not the first.

In any case, "correct for 2 terms" is still not good enough. For the three terms given, I see"subtract 7, then add 5, then subtract seven, then add five, ..."
 

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