JBD2
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Homework Statement
If \sum_{n=1}^{4}log_{2}x^{n}=80, determine the value of x.
Homework Equations
S_{n} = \frac{a(r^{n}-1)}{r-1}
S_{n} = \frac{rt_{n}-a}{r-1}
The Attempt at a Solution
log_{2}1+log_{2}x^{2}+log_{2}x^{6}+log_{2}x^{12}=80?
log_{2}x^{20} = 80
2^{80}=x^{20}
x=16
Is this right? Or does x have to be + or - 16 or am I just completely wrong?
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